3.874 \(\int \frac{(A+B x) \left (a+b x+c x^2\right )^3}{x^5} \, dx\)

Optimal. Leaf size=156 \[ -\frac{a^3 A}{4 x^4}-\frac{a^2 (a B+3 A b)}{3 x^3}-\frac{3 a \left (A \left (a c+b^2\right )+a b B\right )}{2 x^2}+3 c x \left (a B c+A b c+b^2 B\right )+\log (x) \left (3 a A c^2+6 a b B c+3 A b^2 c+b^3 B\right )-\frac{A \left (6 a b c+b^3\right )+3 a B \left (a c+b^2\right )}{x}+\frac{1}{2} c^2 x^2 (A c+3 b B)+\frac{1}{3} B c^3 x^3 \]

[Out]

-(a^3*A)/(4*x^4) - (a^2*(3*A*b + a*B))/(3*x^3) - (3*a*(a*b*B + A*(b^2 + a*c)))/(
2*x^2) - (3*a*B*(b^2 + a*c) + A*(b^3 + 6*a*b*c))/x + 3*c*(b^2*B + A*b*c + a*B*c)
*x + (c^2*(3*b*B + A*c)*x^2)/2 + (B*c^3*x^3)/3 + (b^3*B + 3*A*b^2*c + 6*a*b*B*c
+ 3*a*A*c^2)*Log[x]

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Rubi [A]  time = 0.318172, antiderivative size = 156, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.048 \[ -\frac{a^3 A}{4 x^4}-\frac{a^2 (a B+3 A b)}{3 x^3}-\frac{3 a \left (A \left (a c+b^2\right )+a b B\right )}{2 x^2}+3 c x \left (a B c+A b c+b^2 B\right )+\log (x) \left (3 a A c^2+6 a b B c+3 A b^2 c+b^3 B\right )-\frac{A \left (6 a b c+b^3\right )+3 a B \left (a c+b^2\right )}{x}+\frac{1}{2} c^2 x^2 (A c+3 b B)+\frac{1}{3} B c^3 x^3 \]

Antiderivative was successfully verified.

[In]  Int[((A + B*x)*(a + b*x + c*x^2)^3)/x^5,x]

[Out]

-(a^3*A)/(4*x^4) - (a^2*(3*A*b + a*B))/(3*x^3) - (3*a*(a*b*B + A*(b^2 + a*c)))/(
2*x^2) - (3*a*B*(b^2 + a*c) + A*(b^3 + 6*a*b*c))/x + 3*c*(b^2*B + A*b*c + a*B*c)
*x + (c^2*(3*b*B + A*c)*x^2)/2 + (B*c^3*x^3)/3 + (b^3*B + 3*A*b^2*c + 6*a*b*B*c
+ 3*a*A*c^2)*Log[x]

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Rubi in Sympy [F]  time = 0., size = 0, normalized size = 0. \[ - \frac{A a^{3}}{4 x^{4}} + \frac{B c^{3} x^{3}}{3} - \frac{a^{2} \left (3 A b + B a\right )}{3 x^{3}} - \frac{3 a \left (A a c + A b^{2} + B a b\right )}{2 x^{2}} + c^{2} \left (A c + 3 B b\right ) \int x\, dx + 3 c x \left (A b c + B \left (a c + b^{2}\right )\right ) + \left (3 A a c^{2} + 3 A b^{2} c + 6 B a b c + B b^{3}\right ) \log{\left (x \right )} - \frac{6 A a b c + A b^{3} + 3 B a^{2} c + 3 B a b^{2}}{x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate((B*x+A)*(c*x**2+b*x+a)**3/x**5,x)

[Out]

-A*a**3/(4*x**4) + B*c**3*x**3/3 - a**2*(3*A*b + B*a)/(3*x**3) - 3*a*(A*a*c + A*
b**2 + B*a*b)/(2*x**2) + c**2*(A*c + 3*B*b)*Integral(x, x) + 3*c*x*(A*b*c + B*(a
*c + b**2)) + (3*A*a*c**2 + 3*A*b**2*c + 6*B*a*b*c + B*b**3)*log(x) - (6*A*a*b*c
 + A*b**3 + 3*B*a**2*c + 3*B*a*b**2)/x

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Mathematica [A]  time = 0.152108, size = 154, normalized size = 0.99 \[ \frac{-3 a^3 A-4 a^2 x (a B+3 A b)+36 c x^5 \left (a B c+A b c+b^2 B\right )-18 a x^2 \left (A \left (a c+b^2\right )+a b B\right )+12 x^4 \log (x) \left (3 a A c^2+6 a b B c+3 A b^2 c+b^3 B\right )-12 x^3 \left (A \left (6 a b c+b^3\right )+3 a B \left (a c+b^2\right )\right )+6 c^2 x^6 (A c+3 b B)+4 B c^3 x^7}{12 x^4} \]

Antiderivative was successfully verified.

[In]  Integrate[((A + B*x)*(a + b*x + c*x^2)^3)/x^5,x]

[Out]

(-3*a^3*A - 4*a^2*(3*A*b + a*B)*x - 18*a*(a*b*B + A*(b^2 + a*c))*x^2 - 12*(3*a*B
*(b^2 + a*c) + A*(b^3 + 6*a*b*c))*x^3 + 36*c*(b^2*B + A*b*c + a*B*c)*x^5 + 6*c^2
*(3*b*B + A*c)*x^6 + 4*B*c^3*x^7 + 12*(b^3*B + 3*A*b^2*c + 6*a*b*B*c + 3*a*A*c^2
)*x^4*Log[x])/(12*x^4)

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Maple [A]  time = 0.012, size = 183, normalized size = 1.2 \[{\frac{B{c}^{3}{x}^{3}}{3}}+{\frac{A{x}^{2}{c}^{3}}{2}}+{\frac{3\,B{x}^{2}b{c}^{2}}{2}}+3\,Axb{c}^{2}+3\,Bxa{c}^{2}+3\,Bx{b}^{2}c+3\,A\ln \left ( x \right ) a{c}^{2}+3\,A\ln \left ( x \right ){b}^{2}c+6\,B\ln \left ( x \right ) abc+B{b}^{3}\ln \left ( x \right ) -{\frac{A{a}^{3}}{4\,{x}^{4}}}-{\frac{A{a}^{2}b}{{x}^{3}}}-{\frac{B{a}^{3}}{3\,{x}^{3}}}-{\frac{3\,A{a}^{2}c}{2\,{x}^{2}}}-{\frac{3\,a{b}^{2}A}{2\,{x}^{2}}}-{\frac{3\,B{a}^{2}b}{2\,{x}^{2}}}-6\,{\frac{Aabc}{x}}-{\frac{A{b}^{3}}{x}}-3\,{\frac{B{a}^{2}c}{x}}-3\,{\frac{a{b}^{2}B}{x}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int((B*x+A)*(c*x^2+b*x+a)^3/x^5,x)

[Out]

1/3*B*c^3*x^3+1/2*A*x^2*c^3+3/2*B*x^2*b*c^2+3*A*x*b*c^2+3*B*x*a*c^2+3*B*x*b^2*c+
3*A*ln(x)*a*c^2+3*A*ln(x)*b^2*c+6*B*ln(x)*a*b*c+B*b^3*ln(x)-1/4*a^3*A/x^4-a^2/x^
3*A*b-1/3*a^3/x^3*B-3/2*a^2/x^2*A*c-3/2*a/x^2*b^2*A-3/2*a^2/x^2*b*B-6/x*A*a*b*c-
A*b^3/x-3/x*B*a^2*c-3/x*a*b^2*B

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Maxima [A]  time = 0.696794, size = 220, normalized size = 1.41 \[ \frac{1}{3} \, B c^{3} x^{3} + \frac{1}{2} \,{\left (3 \, B b c^{2} + A c^{3}\right )} x^{2} + 3 \,{\left (B b^{2} c +{\left (B a + A b\right )} c^{2}\right )} x +{\left (B b^{3} + 3 \, A a c^{2} + 3 \,{\left (2 \, B a b + A b^{2}\right )} c\right )} \log \left (x\right ) - \frac{3 \, A a^{3} + 12 \,{\left (3 \, B a b^{2} + A b^{3} + 3 \,{\left (B a^{2} + 2 \, A a b\right )} c\right )} x^{3} + 18 \,{\left (B a^{2} b + A a b^{2} + A a^{2} c\right )} x^{2} + 4 \,{\left (B a^{3} + 3 \, A a^{2} b\right )} x}{12 \, x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x^2 + b*x + a)^3*(B*x + A)/x^5,x, algorithm="maxima")

[Out]

1/3*B*c^3*x^3 + 1/2*(3*B*b*c^2 + A*c^3)*x^2 + 3*(B*b^2*c + (B*a + A*b)*c^2)*x +
(B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*log(x) - 1/12*(3*A*a^3 + 12*(3*B*a*b
^2 + A*b^3 + 3*(B*a^2 + 2*A*a*b)*c)*x^3 + 18*(B*a^2*b + A*a*b^2 + A*a^2*c)*x^2 +
 4*(B*a^3 + 3*A*a^2*b)*x)/x^4

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Fricas [A]  time = 0.298756, size = 227, normalized size = 1.46 \[ \frac{4 \, B c^{3} x^{7} + 6 \,{\left (3 \, B b c^{2} + A c^{3}\right )} x^{6} + 36 \,{\left (B b^{2} c +{\left (B a + A b\right )} c^{2}\right )} x^{5} + 12 \,{\left (B b^{3} + 3 \, A a c^{2} + 3 \,{\left (2 \, B a b + A b^{2}\right )} c\right )} x^{4} \log \left (x\right ) - 3 \, A a^{3} - 12 \,{\left (3 \, B a b^{2} + A b^{3} + 3 \,{\left (B a^{2} + 2 \, A a b\right )} c\right )} x^{3} - 18 \,{\left (B a^{2} b + A a b^{2} + A a^{2} c\right )} x^{2} - 4 \,{\left (B a^{3} + 3 \, A a^{2} b\right )} x}{12 \, x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x^2 + b*x + a)^3*(B*x + A)/x^5,x, algorithm="fricas")

[Out]

1/12*(4*B*c^3*x^7 + 6*(3*B*b*c^2 + A*c^3)*x^6 + 36*(B*b^2*c + (B*a + A*b)*c^2)*x
^5 + 12*(B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*x^4*log(x) - 3*A*a^3 - 12*(3
*B*a*b^2 + A*b^3 + 3*(B*a^2 + 2*A*a*b)*c)*x^3 - 18*(B*a^2*b + A*a*b^2 + A*a^2*c)
*x^2 - 4*(B*a^3 + 3*A*a^2*b)*x)/x^4

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Sympy [A]  time = 16.0487, size = 184, normalized size = 1.18 \[ \frac{B c^{3} x^{3}}{3} + x^{2} \left (\frac{A c^{3}}{2} + \frac{3 B b c^{2}}{2}\right ) + x \left (3 A b c^{2} + 3 B a c^{2} + 3 B b^{2} c\right ) + \left (3 A a c^{2} + 3 A b^{2} c + 6 B a b c + B b^{3}\right ) \log{\left (x \right )} - \frac{3 A a^{3} + x^{3} \left (72 A a b c + 12 A b^{3} + 36 B a^{2} c + 36 B a b^{2}\right ) + x^{2} \left (18 A a^{2} c + 18 A a b^{2} + 18 B a^{2} b\right ) + x \left (12 A a^{2} b + 4 B a^{3}\right )}{12 x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x+A)*(c*x**2+b*x+a)**3/x**5,x)

[Out]

B*c**3*x**3/3 + x**2*(A*c**3/2 + 3*B*b*c**2/2) + x*(3*A*b*c**2 + 3*B*a*c**2 + 3*
B*b**2*c) + (3*A*a*c**2 + 3*A*b**2*c + 6*B*a*b*c + B*b**3)*log(x) - (3*A*a**3 +
x**3*(72*A*a*b*c + 12*A*b**3 + 36*B*a**2*c + 36*B*a*b**2) + x**2*(18*A*a**2*c +
18*A*a*b**2 + 18*B*a**2*b) + x*(12*A*a**2*b + 4*B*a**3))/(12*x**4)

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GIAC/XCAS [A]  time = 0.272779, size = 224, normalized size = 1.44 \[ \frac{1}{3} \, B c^{3} x^{3} + \frac{3}{2} \, B b c^{2} x^{2} + \frac{1}{2} \, A c^{3} x^{2} + 3 \, B b^{2} c x + 3 \, B a c^{2} x + 3 \, A b c^{2} x +{\left (B b^{3} + 6 \, B a b c + 3 \, A b^{2} c + 3 \, A a c^{2}\right )}{\rm ln}\left ({\left | x \right |}\right ) - \frac{3 \, A a^{3} + 12 \,{\left (3 \, B a b^{2} + A b^{3} + 3 \, B a^{2} c + 6 \, A a b c\right )} x^{3} + 18 \,{\left (B a^{2} b + A a b^{2} + A a^{2} c\right )} x^{2} + 4 \,{\left (B a^{3} + 3 \, A a^{2} b\right )} x}{12 \, x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x^2 + b*x + a)^3*(B*x + A)/x^5,x, algorithm="giac")

[Out]

1/3*B*c^3*x^3 + 3/2*B*b*c^2*x^2 + 1/2*A*c^3*x^2 + 3*B*b^2*c*x + 3*B*a*c^2*x + 3*
A*b*c^2*x + (B*b^3 + 6*B*a*b*c + 3*A*b^2*c + 3*A*a*c^2)*ln(abs(x)) - 1/12*(3*A*a
^3 + 12*(3*B*a*b^2 + A*b^3 + 3*B*a^2*c + 6*A*a*b*c)*x^3 + 18*(B*a^2*b + A*a*b^2
+ A*a^2*c)*x^2 + 4*(B*a^3 + 3*A*a^2*b)*x)/x^4